Question

Question Help Use technology and the given confidence level and sample data to find the confidence interval for the population mean u. Assume that the population does not exhibit a normal distribution Weight lost on a diet 98% confidence n=61 x=4.0 kg s=5.9 kg What is the confidence interval for the population mean ? kg<u-kg (Round to one decimal place as needed)

Answer 1

Solution Given Sample size. Nr 61 Sample mean X= 4.0 Sample standard deviation (3)= 5.9 Contidence interval = 0.98 = 1-0.98 0.02 0.02 = 0.01 affic z Z 2.3263 7212 2.3263 rodont EYYO Y Margin of 2/2 x Sorg ME= a. 326 3 X5: 7 VGI 22 13.72517 -1.757 7.87024968 IME = 1.757. Lower bound x - 3 Vn 2.3Q63 X5.9

13.72519 7,81024968 4-1.75732 794 Lower Bound = 2.24267206 ~ a 2.2 lepper Bound =x+ ? /*S Vol - 4+ 2.326 3 159 Vol 13.72517 ut 7-81024968 =ut 175732794 upper Bound -5.75732794 a 5.8 Thes Confidencen centerval is [ (2.2, 5.8) The Confidence interval for the population mean M is 2.2 kg <M<5.8 kg. Please and me Thank you like Support