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For the reaction below, if 8.0 mol of Fe and 5.0 mol of O2were mixed, how...

For the reaction below, if 8.0 mol of Fe and 5.0 mol of O2were mixed, how many moles of the excess reagent would remain?4 Fe(s)+3 O2 (g) → 2 Fe2O3(s)

I know the answer is 1.3 mol Fe..... but i do not understand the steps and reasoning behind the steps. Please explain.

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Answer #1

8 ATasn frem the reaton but given moles of te cess reagent exces8yenent left over 8-6-7

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