a)
this is abuffer so
pH = pKa + log(NaCHO2/HCHO2)
NaCHO2 = MV = 55*0.15 = 8.25
HCHO2 = MV = 70*0.13 = 9.1
pH = 3.75 + log(8.25/9.1) = 3.707
B)
pOH = pKB + log(NH4/NH3)
NH4= MV = 0.13*120 = 15.6
NH3 = MV = 0.13*260 = 33.8
pOH = 4.75 + log(15.6/33.8 )=5.9431
pH = 14-5.9431
pH = 8.0569
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