Question

AutoSave Of H b Sample Question630 - Excel S earch O X Comments File Home Insert Draw Page Layout Formulas Data Review View Help === D a Wrap Text General Amrit Batth AB - Share PD SEX E' 47 0 5 Conditional Format as Cell Insert Delete Format Sort & Find & Ideas Formatting Table Styles Filter Select Styles Cells Editing Ideas Times New Roman 12 AA BIU DA LE Paste SE E E Merge & Center $ % , 4 00 " Clipboard Font Alignment Number S21 B E F G H I J K L M N O P Q R Sample Irregularities Question 3: A textile manufacturer wants to set up a control chart for irregularities (e.g., oil stains, shop soil, loose threads, and tears) per 100 square yards of carpet. The following data were collected from a sample of twenty 100 a. Using these data, set up a control chart with z = 3. b. Suppose that the next five samples had 17, 19, 22, 19, and 16 irregularities. What do you conclude?- square-yard pieces of carpet: Upper control limit = UCLP = P + zop Lower control limit = LCL, = p - Zop 10 Upper control limit - UCL - + VC Lower control limit = LCL - T - ZVE Op = V7(1 - pin Upper control limit = UCL = x + Zot Lower control limit = LCL 7-zor 15 16 17 18 19 20 Total 13 239 Unner control limit = UCL-= 7+ AR Q1) SPC Q2) SPC Q3) SPC 04) QDM Z-Chart 3 Sigma Table Factor 4 @ J -- + + 12:48 PM 2020-03-04 Type here to search o i wa 9р A x ENG 2

Answer 1

a.

p-bar = total no of defectives/(no of samples*sample size) = 239/(20*100) = 0.1195

Sp = sqrt((p-bar*(1-p-bar))/sample size) = sqrt((0.1195*(1-0.1195))/100) = 0.032437594

Upper control limit = p-bar + z*Sp = 0.1195+3*0.032437594 = 0.216812782

Lower control limit = p-bar - z*Sp = 0.1195-3*0.032437594 = 0.022187218

b.

The process is within control statistically as all the samples are within statistical control