Question

A professional golfer is examining a video of a practice swing. The high‑speed footage shows that his club is in contact with the ball (which was initially at rest on the tee) for only Δ?=0.371 ms, and the radar gun clocks the speed of the ball as ?b=131 mph after it comes off the club. The golf ball has a mass of ?b=45.9 g.

What is the magnitude of the impulse imparted to the ball by the club?

magnitude of the impulse:____ kg⋅m/s

What is the magnitude of the average force of contact between the club and the ball?

magnitude of the average force of contact: _____N

Answer 1

I By definition, the Impulse of force is defined as (1) = Force (F) x H me (f). - FXE - from Newton's and low of motion Force (F) = Mars (m) x accefur alion () F = ma. again acceperation (al change of relocity time (t.) a & Bu putting these values in (1) weget, 1- 2 + xt = nu — 7. Le . mu-mu. according to question, vao (incsially sest). I 2 MV - (21 & a 131 mp h. 131 x 1.609 kph. limph=160148h v = 13101.609 kpl 1kph 1000 moh. v = 131x):609x mis V 59.55 m/s from (2) I-mo = 45.9 x 58.55 kg. m/s. 0 mps 5) 1 = 2.69 teg. m/s.

hverage for le TFs Mass x average acederaliong) (- mca) change of velocity time (At) Giren dala, again Lay - La) - vv M= 45.gg men og kg At At-0.311ms = 0.3718 10's &U=0 m/s. mv АР. N. LE - 45.9 x 58.55 1000 0.3714103 L.) – 7243.8N. -