Question

6:18 LTE O < 48C Law of Cosines a... Q Q ☺ 3. A pilot is landing her plane. The airport has a runway that is 9000 feet long. The angle of depression from the plane to the start of the runway is 18.8 degrees and the angle of depression to the end of the runway is 17.5 degrees. Find the distance the plane will travel to land the plane at the start of the runway.

Answer 1

So 9000 feet L SAA - 18.80 degrees LEPA - 17.5 degrees (SPA-LPSO [Allennate interior angles / Similarly. LEPA LPEO. (Pos. (POE: 90° [By constinction] Let os be x feet. Now, in APEO, tas (LPEO] & perpendicular - po base tan (17.5°) = . Po x+9000 approximately I => x+9000 0.315 , po PO = 0.315(x + 9000) => Po = 0.315 x + 2835 Again, in & Pso . perpendicular po os base ton (Leso) - perpendiculas tan (18.8°) - PO 0.340 - so (approximately] » PO = 0.340x

Equalis & Equalis 2 0.3152 2835 - 0.340 x 8855 -0.340 2 – 0.315 & 2335 0.025 2 X 2835 > -) -> Agan. * = 773400 in 4 Pso. cos (Leso) = base Bypo leniwe cos (€ 18.8°) - 113400 PS >> 5) [approximate I 0.966 - 173400 as = 113400 - ps » 0.946 = 119873.1501 (approx.) . The distance which the plane will travel to land the plane at the start of the runway is 119873.15 feet (approx )