Question

For the answer please have the correct number of signifcant figures

What is the orbital period of a satellite placed in an orbit 1.60 x 10 km above Earth's surface? Earth - 6.38 x 106m MEarth - 5.98 x 1024 kg Give your answer in minutes to the correct number of significant figures (3 in this case)

Answer 1

And earth= 5.98x1024 kg, G = 6.67 x 10" Nm?) kg? 6.38 x 106m +1.80x106m 7.98 X10m ... T= za the 73 GM 2x 3.14 X (7.98x105)3 6,67 X10-1 X 5.97 X 1024 6.28x 12,74 X 105 T= 6,28 x 508.1696X 1018 39.887 X 1013 6.28 x 102 X 11.2872 1.18 x 102 minute T = 7.09 x103 seconds IT-

Ansy Mearth 5.9 8 X 1024 8x1024 kg G = 6.67X10 Nm Nm2/kg 2 6.38 X10m + 1.6x106m 7.98 X10 ra 6 T= za 83 GM 2x 3.14 X (7.9881063 6,67 X10-1) X 5.98 X 1024 6.28 x 12.74 X 105 T= 6,28 x 508.1696X 1018 39.887 X 1013 6.28 X 10PX 11.2872 T 11 7.09 X103 seconds T = 4. 18. X103 minute