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Question 1, Part 2: A student crossed two flies and collected Fl progeny. The first parental...
We crossed pure-bred female flies with yellow body and forked-shaped bristles with male flies extra bristles....
We crossed pure-bred female flies with yellow body and
forked-shaped bristles with male flies extra bristles. The
subsequent F1 flies showed all normal phenotypes except that all of
the F1 males are yellow-body. We crossed again the normal F1
females with males homozygous for yellow body, extra bristles, and
forked bristles as a testcross. The number of each category of F2
progeny is shown below. The mutant allele for yellow body is y; the
mutant allele for extra bristles is...
Question 5 (14 marks) The allele cn gives fruit flies cinnabar eyes, whereas the allele cn...
Question 5 (14 marks) The allele cn gives fruit flies cinnabar eyes, whereas the allele cn gives red, the wild-type phenotype. The allele wx of a separate allele gives waxy wings, and wx gives non-waxy wings (wild-type). The allele b of a third gene gives fruit flies a black body, whereas the allele b gives a brown (wild-type) body colour. A geneticist knows these three genes are on the same chromosome, but does not know what order the genes are...
Drosophilia homozygous for the lobed eye mutation (L) were mated with flies homozygous for a wing...
Drosophilia homozygous for the lobed eye mutation (L) were mated with flies homozygous for a wing mutation known as plexus (px) All the f1 progeny had lobed eyes and wild type wings. The F1 flies were test crossed resulting in the following progeny: Number 18 F2 phenotypes Wild type eyes and wings Lobed eyes Plexus wings Lobed eyes and plexus wings 35 33 14 Write the genotypes of the parental and f1 flies. Use proper drosophilia nomenclature. Be sure to...
feel like I did these wrong numbers too high on first problem? how do you know...
feel like I did these wrong
numbers too high on first problem?
how do you know which gene is in the middle?
thank you.
Question #1 . To determine the)rder of three genes, a cross was set up fly was homozygous for three mutations - cherub wings (cw), black body (b), and cinnabar eyes cn). The other fly was homozygous wild type for all three genes (cw b cn). F1 females from the cross were test-crossed with cherub, black, and...
2. You cross a homozygous wildtype female Drosophila (fruit fly) with a male that has a black body (bb). You mate two of the F1 (first generation) flies and examine the F2 (second generation) off...
2. You cross a homozygous wildtype female Drosophila (fruit fly) with a male that has a black body (bb). You mate two of the F1 (first generation) flies and examine the F2 (second generation) offspring. The phenotypes can be seen in the table below. a. Draw a pedigree to show the P, F1, and F2 generations. You only need to draw one fly with each phenotype for the F2 generation. seen in this cross. the expected values for a cross...
all of them please Question 10 (1 point) In Drosophila, the mutant black (b) has a...
all of them please
Question 10 (1 point) In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (V+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
5. You started working in a Drospohila lab. You are studying two different autosomal traits, body...
5. You started working in a Drospohila lab. You are studying two different autosomal traits, body color and antennae length. Gray body (B) is completely dominant to black body (b) and long antennae length (A) is completely dominant to short antennae length (a). You cross true-breeding gray bodied, long antennae files to true-breeding black bodied, short antennae. The F1 progeny all have gray bodies and long antennae. a. You perform a testcross to the F1 progeny produced from the parent...
all please Question 2 (1 point) ✓ Saved In Drosophila, the mutant black (b) has a...
all please
Question 2 (1 point) ✓ Saved In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (v+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
We crossed pure-bred female flies with yellow body and
forked-shaped bristles with male flies extra bristles. The
subsequent F1 flies showed all normal phenotypes except that all of
the F1 males are yellow-body. We crossed again the normal F1
females with males homozygous for yellow body, extra bristles, and
forked bristles as a testcross. The number of each category of F2
progeny is shown below. The mutant allele for yellow body is y; the
mutant allele for extra bristles is...
Question 5 (14 marks) The allele cn gives fruit flies cinnabar eyes, whereas the allele cn gives red, the wild-type phenotype. The allele wx of a separate allele gives waxy wings, and wx gives non-waxy wings (wild-type). The allele b of a third gene gives fruit flies a black body, whereas the allele b gives a brown (wild-type) body colour. A geneticist knows these three genes are on the same chromosome, but does not know what order the genes are...
Drosophilia homozygous for the lobed eye mutation (L) were mated with flies homozygous for a wing mutation known as plexus (px) All the f1 progeny had lobed eyes and wild type wings. The F1 flies were test crossed resulting in the following progeny: Number 18 F2 phenotypes Wild type eyes and wings Lobed eyes Plexus wings Lobed eyes and plexus wings 35 33 14 Write the genotypes of the parental and f1 flies. Use proper drosophilia nomenclature. Be sure to...
feel like I did these wrong
numbers too high on first problem?
how do you know which gene is in the middle?
thank you.
Question #1 . To determine the)rder of three genes, a cross was set up fly was homozygous for three mutations - cherub wings (cw), black body (b), and cinnabar eyes cn). The other fly was homozygous wild type for all three genes (cw b cn). F1 females from the cross were test-crossed with cherub, black, and...
2. You cross a homozygous wildtype female Drosophila (fruit fly) with a male that has a black body (bb). You mate two of the F1 (first generation) flies and examine the F2 (second generation) offspring. The phenotypes can be seen in the table below. a. Draw a pedigree to show the P, F1, and F2 generations. You only need to draw one fly with each phenotype for the F2 generation. seen in this cross. the expected values for a cross...
all of them please
Question 10 (1 point) In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (V+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
5. You started working in a Drospohila lab. You are studying two different autosomal traits, body color and antennae length. Gray body (B) is completely dominant to black body (b) and long antennae length (A) is completely dominant to short antennae length (a). You cross true-breeding gray bodied, long antennae files to true-breeding black bodied, short antennae. The F1 progeny all have gray bodies and long antennae. a. You perform a testcross to the F1 progeny produced from the parent...
all please
Question 2 (1 point) ✓ Saved In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (v+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...
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