Question

STA 4963 Homework 2 Problem 5 An urn contains six red balls and three blue balls. One ball is selected at random and is replaced by a ball of the other color. A second ball is then chosen. What is the conditional probability that the first ball selected is red, given that the second ball was red? Possible Answers A 10/27 B 10/17

Answer 1

Gillen G Red & 3 blue balls P (Rin Rz) PLR2) PCR, R2) P (R2) = p (R. and R2) + P(R. and R2) - 17127 P (R. & R2) = 8 x 55 P (R, IR2) = 10/27 17127 = 10/17 option (6) is correct

2 Les dentes vi mot en carbasy y devo serviral cen t e contar P (1 in 301x) - 300, (0.9% 0.1) Painzoly) - 300 6.93 2002 3340 Probabili 0.1413 × 15 1513x45 +0:3340415 = 0 955 0*10 option (A) is correct. P(1 in 301x) is the probability that ineffective rizal from company a. PC linoly) is the probability that ineffective vival is from other company. Finally to find the Conditional Probability that viral wass ineffective & it came from company & we use the bayes theorem.