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9. Find the dimensions of a rectangle with perimeter 100 m whose area is as large as possible.
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Given that! Pestimeters of Stectangle = 100 m. let het Length width of of sectangle rectangle = rem = y m . So, perimeter = 22x = so X = sto = 25 m 1 x = 25 m Y = 5o - x 50 - 25 sol = x= 25m Length width of of rectangle Mectangle ay = 25 m please Upplease thumbs up

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Krupal Bandi Thu, Jan 13, 2022 4:52 PM

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