Question

Excess Reactant Examples: 12. Recall from Example 10 that we can extract titanium metal from its oxide according to the following balanced equation: TiO:(s) + 2 C(s)_ Ti(s) + 2 CO(g) Recall further that in a reaction mixture containing 28.6 kg of C and 88.2 kg of TiOz, TiO2 is the limiting reactant. Calculate the mass of the reactant in excess (which is carbon) that remains after the reaction has gone to completion.

Answer 1

TiO2 (s) + 2(15) Tils + 210g mass of c = 28.6 kg = 28600 g no of mole of c= 28600 g = 2383.3 mol 12 gional - 2383.5 mol mars of TiO2 = 88.2kg = 88200g no. of mode of TiO₂ = 88200 g = 1102.5 mol 80 g/mol Acc to ? male TiO2 react with a mole , then 1102.5 male TiO₂ react with 2x1102.5=2205 mol c. no. of mole of excen cremains = 2383.3 mol - 2205 mol = 178.3 mol mans of exces c = 178.3 mal x 129,00 = 2139.69 = 2.1396kg. = 2.14 kg Hence, 2.14kg is the mass of Carbon in excen remains after the reaction has gone to completion.