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5 pts Question 23 Life on Earth uses 3 nucleotide long code words, with 4 letters in the alphabet to encode 20 amino acids. D
5 pts Question 24 The following eukaryotic DNA is transcribed into RNA and the MRNA transcript is translated into protein 31
31 21 11 1 GGC GACGACA TATAAAGCGA CGACTGTAGA CTGATGAGCC 61 71 51 41 TATCCATGGA CGCGCCATGG TCACATAAGC GGTGC GAT GC 101 111 91
5 pts Question 25 The following eukaryotic DNA (same as above) is transcribed into RNA and the MRNA transcript is translated
THE GENETIC CODE SECOND LETTER A G C UCU U UU Phe Uuc U UUA Leu uUG UAU Tyr UAC) Cys UGC UCC Ser UCA UAA (terminator) UGA ter
What is the sequence of the protein translated from this mRNA? N-Met-Ala-Leu-C N-Met-Ser-Leu-C N-Gly-Val-Asn-Ile-C N-Met-Val-
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Answer #1

23- Given that there are three bases.

If there are two bases in one codon then the number of codons will be 3*3 = 9

If there are three bases in one codon then the number of codons will be 3*3*3 = 27

If there are four bases in one codon then the number of codons will be 3*3*3*3 = 81

If there are five bases in one codon then the number of codons will be 3*3*3*3*3 = 343

Given that only 26 amino acids are needed for the Arth organism. So minimum codon could be 26 + 1 (Stop codon)

So the answer is three bases per codon.

Option B is the correct answer.

24 - 11 21 31 GGCGACGACA TATAAAGCGA CGACT GTAGA CT GATGAGCC 51 Coding region 71 TATCCATGGA CGCGCCATGG TCACATAAGC GGTGCGATGC Kozak

As shown in the figure open reading Start codon and ends before stop codon, So in the given sequence open reading frame starts from 57th base and ends at 65th base.

So answer is option B - 57-65.

25- Protein coding sequence is AUG GUC ACA. It encodes for N-terminal  MET VAL THR- C-terminal.

So correct answer is option D - N-Met Val Thr -C

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