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Let's say that in chipmunks, the allele for a black tail stripe (B) is dominant to...

Let's say that in chipmunks, the allele for a black tail stripe (B) is dominant to the allele for a white tail stripe (b), and that the allele for patches of fur on an ear ("ear tufts") is determined by a recessive allele (e), with plain ears resulting from a dominant allele (E). A chipmunk that is homozygous recessive for the tail trait and heterozygous for ear morphology mates with a chipmunk that is heterozygous for both tail and ear morphologies. QUESTION:What is the PHENOTYPIC RATIO of all possible phenotypes (NOT genotypes!) among these parents' offspring for these two traits? Show both Punnett squares(one for each gene), branch diagram, and all math. NOTE:A phenotypic ratio includes both the fraction and the descriptive adjective(s) for each phenotype. Parental genotypes for both genes:____ ____ ____ ____ x ____ ____ ____ ____ Two Punnett squares: Branch Diagram:

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Answer #1

Black tail = BB, Bb

White tail = bb

Plain ear = EE, Ee

Ear tuft = ee

Monkey 1 = Eebb

Monkey 2 = EeBb

Punnett square 1 -

Ee × Ee

Gametes E e
E EE (plain ear) Ee (plain ear)
e Ee (plain ear) ee (ear tuft)

PR = 3 : 1

Bb × bb

Gametes b
B Bb (black tail)
b bb (white)

PR = 1 : 1

Possible phenotype from both the crosses -

E_Bb (plain, black) = 3 × 1 = 3

eeBb (tuft, black) = 1 × 1 = 1

E_bb (plain, white) = 3 × 1 = 3

eebb (tuft, white) = 1 × 1 = 1

PR = 1 : 1 : 3 : 3

Branch diagram

Еex Ee - bb X Bb Bb - LEEBB (Plain, Black) I bb I EE - y EEbb (Plain white) 2 Febb (Plain, black) 2 Ee 2 febb yo (Plain, whit

From the given branched diagram,

Plain black = 3

Plain white = 3

Tuft black = 1

Tuft white = 1

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