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In horses, the color black is due to a dominant allele (B) and chestnut color is...

In horses, the color black is due to a dominant allele (B) and chestnut color is due to a recessive allele (b) of the same gene. The trotting gate is due to a dominant allele (T) and the pacing gate is due to the recessive allele (t) of the same gene. These two genes are located on different chromosomes.

A homozygous black pacer horse mates with a homozygous, chestnut trotting horse and they have a daughter.

a. What are the genotypes for both parents in this cross?

b. What are the genotypes and the phenotype of the daughter for both traits?

Next, the daughter is mated with a homozygous, black, pacer horse.  

c. What gametes would be produced from both the daughter and her mate?

d. What is the phenotypic ratio of the resulting offspring? SHOW YOUR WORK!

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Answer #1

Black = BB, Bb

Chestnut = bb

Trotting gate = TT, Tt

Pacing gate = tt

A. Horse 1 = BBtt

Horse 2 = bbTT

B. BBtt × bbTT = BbTt (black trotting gate daughter)

BbTt (daughter) × BBtt (mate)

C. Gamates by daughter = BT, Bt, bT, bt

Gametes by mate = Bt

D. BbTt × BBtt

Gametes Bt
BT BBTt (black, trotting)
Bt BBtt (black, pacer)
bT BbTt (black, trotting)
bt Bbtt (black, pacer)

Phenotypic ratio = 1 (black trotting) : 1 (black pacer)

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