Question

Your answer is partially correct. Try again. A load of P = 50 kN is supported by a structure consisting of rigid bar ABC, two identical solid bronze [E = 82 GPa, a = 15.7 x 10-6/0C] rods, and a solid steel [E = 197 GPa, a = 12.2 x 10-6/°C]. The bronze rods (1) each have a diameter of 29 mm and they are symmetrically positioned relative to the center rod (2) and the applied load P. Steel rod (2) has a diameter of 16 mm. Assume L2=1.6 m, L2=2.7 m. The bars are unstressed when the structure is assembled. After the temperature of the structure has been increased by 59°C, determine: (a) the normal stresses 01, 02 in the bronze and steel rods. (b) the normal strains El, €2 in the bronze and steel rods. (c) the downward deflection v of rigid bar ABC. (2) L2 (1) L1 OB P 4:00 DM

Answer 1

final extension in steel a final extension in bronze Co 4 A B. АР given Dutai P = 60KN Bur Bronze (E=82GP4, 2=1507x1000 A = 60 6x10m² 01 = 29 mm Burn .-2. steel (Eolgt capa, d=12.2010 12.2x10-6/0) d2 = 16 mm Az = 200lXI6 AT = 59°c L = 1.6m L2=2.7 m from the condition of static equilibrium 2Pb + Ps= 60kN -- cij from compatibility condition 6 LG & St T + Ps Ls 46 db T + Pb Lb As Es Ab Eb -6 (2.7 x 12.2810 x 59)+1 2.02/0"x) (1.67 15-10%254) + IPbx1.6 (6.6x1044 197x106 82x106)

o.oo1943 + o.oooo teste, poolgo.oooo egs fь o.oooo 2454 4Pь - o.oooo signs - о. оооч 63 0, 29 56 РЫo.glѕ Рѕц. 63 -- di) by solving ean (is & cilj Pb= 27, 445 kW Ps 5.1085 км normal stress impa 2 т. и 45 х 33 4. 58 4 - сь Pь Ab 6, 6xtо ч 65 = Ps As 5. 1085 х (03. 25. 4/54 MP4 6, 2 2.olx 10ч 6. ЕЕ NOW 6 = 6, E, €, х (82 x1000) 4. 58 = е : 501.013 ще 62 = Ег .. 25.4 54 5 6 x cig1x1000) ег - 12.0t24

downward de flection of bar final deflection of steel bar or final deflection of bronze A (LSTST t Pals PbLb Ab Eb As Es A = (2-7X1000 x 18.2x106x 59) + (5.108510 x 2.7X10%) (201.0619 x 1g7x103) = logug46 + 0.34822 2,29168 mm A 2. 3 mm