Question

all answer please

ion 4: For the following series-parallel circuit: 1) The total impedance in rectangular form (10pts): 2) The current Iez through the resistor R2 in time domain (10pts): C1 R1 We :: : 630.7 Ohs R3 820 R2 ..3L1 2V 30 H oDeg . 82mH

Answer 1

Given: input, v_1 = 12 angle 0 degree at f_0 = 30 Hz inductor impedance: j w_0 L_1 = j 2 pi f_0 L_1 = j (2 pi times 30 times 82 times 10^-3) = j (15.456) = 15.45 angle 90 degree capacitor impedance: 1/j w_0 c = 1/j 2 pi f_0 c_1 = xc/j = 1/j times 2 pi times 30 times c_1 = 530.79/j = 530.79 angle -90 degree 1 Total impedance: Here capacitor and Resistor in series so x_1 = R_3 - j x_c = 8.2 - j (530.79) = 530.85 angle 89.11 degree \r\n Now: inductor and X_1 are parallel, so x_2 = (15.46 angle 90 degree) (530.85 angle -89.11 degree)/(15.46 j) + (8.2 - 530.79 j) = 8207 angle 0.885 degree/8.2 - 515.33 j = 8207 angle 0.885 degree/515.39 angle -89.08 degree x_2 = 15.92 angle 90.685 = -0.19 + 15.92 j Now R_2 is parallel with x_2: then x_3 = 6.8 times 15.92 angle 90.685/6.8 + (-0.19 + 15.92 j)