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Question 20 1 pts The rms value of the electric field in an electromagnetic wave is...
The amplitude of the electric field in the electromagnetic wave is Erms = 840 V/m. The intensity of this wave is a) 937 W/m2 b) 614 W/m2 c) 747 W/m2 d) 455 W/m2 e) 1150 W/m2
A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of Erms = 2.0 × 109 N/C. Find the average power of each pulse that passes through a 1.6 × 10-5-m2 surface that is perpendicular to the laser beam. A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of E 2.0 x 109 NIC. Find the average...
What is the maximum value of the electric field in an electromagnetic wave whose average intensity is 7.10 W/m2 ?
A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of Erms = 2.50 109 N/C. Find the average power of each pulse that passes through a 2.40 10-5 m2 surface that is perpendicular to the beam.
#4 part a,b,c 4. An electromagnetic wave with a frequency of 100,0 MHz, İs traveling direction. Att-0 s, the electric field due to this wave of 300.0 V/m. through a vacuum in x- (i) What is the wavelength of this wave? a. 1.0 m b. 2.0 m c, 3.0 m d. 4.0 m (ii) What is the amplitude of the magnetic field due to this wave? a, 1.0 μΤ b, 2.0 μ T c. 3.0 uT d. 4.0 HT (iii)...
The maximum magnitude of the magnetic field in an electromagnetic wave is 499 μT. What is the maximum magnitude of the electric field in this wave? V/m The magnetic field in an electromagnetic wave has a peak value given by 374 μT. What is the peak intensity of this wave? W/m2 Tries 0/2 What is the average intensity of this wave? W/m2
The magnetic field in an electromagnetic wave has a peak value given by B = 3.5?T . Part A For this wave, find the peak electric field strength. Express your answer using two significant figures. E = kV/m SubmitMy AnswersGive Up Part B Find the peak intensity. Express your answer using two significant figures. I = kW/m2 SubmitMy AnswersGive Up Part C Find the average intensity. Express your answer using two significant figures. Iav = kW/m2
Which of the following is a possible equation for the electric field of an electromagnetic wave with average intensity 0.00132W/m2 traveling in the +z direction with a magnetic field along the x axis? a. ?=(2 V/m) sin [(9.8x106 /m)z + (2.9x10^15 Hz)t] ?̂ b. ?=(1 V/m) sin [(9.8x106 /m)z - (2.9x10^15 Hz)t] ?̂ c. ?=(1 V/m) sin [(9.8x106 /m)z - (2.9x10^15 Hz)t] ?̂ d. ?=(2 V/m) sin [(9.8x106 /m)z + (2.9x10^15 Hz)t] ?̂ Which of the following is a possible...
A traveling electromagnetic wave in a vacuum has an electric field amplitude of 52.7 V/m. Calculate the intensity S of this wave. Then, determine the amount of energy U that flows through area of 0.0293 m2 over an interval of 11.9 s, assuming that the area is perpendicular to the direction of wave propagation. W S = m2 U = J
A traveling electromagnetic wave in a vacuum has an electric field amplitude of 68.7 V/m. Calculate the intensity S of this wave. Then, determine the amount of energy U that flows through area of 0.0225 m2 over an interval of 18.9 s , assuming that the area is perpendicular to the direction of wave propagation. S= W/m2 U= J