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Help with part F
nes n=4 E-0.85eV E--1.33eV 8 The energy level diagram at right shows the first five energy levels for an imaginary atom. A. W
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Answer a) For n=1 to n=u excitation AE = (21.3-1.33) eV hf ; h= planks constant 1997 x 7.6x1079 ASI DE f = AE h 6.626 X 10-3AE = hc Af [ As forequence alredy calulated] Af=c 3x108 7 = 2 с f 15 4.822 X10 = 0.622 x167 6.022 x108m The energy energy of

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