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If we start with 25.0 mL of 0.100 M sodium methoxide and 25.0 g of 2-bromobutane,...
Elimination Reactions Prelab Date 1. Explain why we get a different product when we use bulky...
Elimination Reactions Prelab Date 1. Explain why we get a different product when we use bulky bases compared to smal bases. (3 pts) 2. If we start with 25.0 mL of 0.100 M sodium methoxide and 25.0 g of 2-bromobutane, what will be the theoretical yield of your product? (Use dimensional analysis/ Do not break up your steps/Read the beginning of your lab to guide you on how to do this problem). (3 pts) 3. How can one determine which...
1. How many mL of 0.100 M NaOH are required to neutralize (or titrate) 25.0 mL...
1. How many mL of 0.100 M NaOH are required to neutralize (or titrate) 25.0 mL of 0.15 M H,Po.? Write the balanced acid-base neutralization reaction to start. (12 pts)
3 part question Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109...
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
please help!! A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron...
please help!!
A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (II) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) – Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here
2. A 25.0 mL sample of unknown HBr is titrated with 0.100 M (NaOH). The equivalence...
2. A 25.0 mL sample of unknown HBr is titrated with 0.100 M (NaOH). The equivalence point is reached upon the addition of 18.36 mL of the base Calculate the concentration of the unknown HBr (25 pts)
Q4 Solution Stoichiometry 10 Points A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml...
Q4 Solution Stoichiometry 10 Points A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (III) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) ► Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here Please select...
3. If sodium methoxide in methanol was used in place of potassium t butanol, your GC...
3. If sodium methoxide in methanol was used in place of potassium t butanol, your GC analysis would look much more like the 2-butanol/sulfuric acid reaction products. In addition, a new, non-alkene product would be present in the GC analysis from a competing, non-elimination mechanism. Explain why the alkene distribution would change, what the new product would be, and why this new product would form. 4. If 2-bromobutane was reacted with trimethylamine to produce sec-butyl trimethyl- ammonium bromide (see below),...
E. Titration calculations 1. A 25.0-ml sample of 0.100 M HCl is titrated with 0.125 M...
E. Titration calculations 1. A 25.0-ml sample of 0.100 M HCl is titrated with 0.125 M NaOH. How many milliliters of the titrant will be need to reach the equivalence point? 2. A 25.0-ml sample of 0.100 M Ba(OH)2 is titrated with 0.125 M HCI. How many milliliters of the titrant will be need to reach the equivalence point? 3. For the following titrations, determine if the equivalence points will be acidic, basic, or neutral i. NH3 titrated with HCI...
Procedure: Measure and dispense 0.6 ml of a 4.4 M otion of sodium methoxide in methanol...
Procedure: Measure and dispense 0.6 ml of a 4.4 M otion of sodium methoxide in methanol and me of ethanol into a 5 mL reaction vial. Add 2.5 mmol of acetaminophen (40.378. Set up for reflux in the rume hood and bring reaction to reflux for 15 minutes (solvent is boiling and vapors are condensing condenser). After 15 minutes, directly through the top of the condenser tube, carefully add 0.3 ml of iemy iodide. Continue to reflux for another 45...
0.100 molar weak acid HA vs 0.100 molar NaOH Start with 25.0 mL HA I will...
0.100 molar weak acid HA vs 0.100 molar NaOH Start with 25.0 mL HA I will provide a blank graph if you want to use it to fill in the points. You can use a pencil and take a picture) or 'draw'. Or you can use a graphing program. Please answer questions, 2 points each According to this data: What is the pka of the acid? What is [H*) at the Equivalence point? What is the [OH-] at the Equivalence...
Elimination Reactions Prelab Date 1. Explain why we get a different product when we use bulky bases compared to smal bases. (3 pts) 2. If we start with 25.0 mL of 0.100 M sodium methoxide and 25.0 g of 2-bromobutane, what will be the theoretical yield of your product? (Use dimensional analysis/ Do not break up your steps/Read the beginning of your lab to guide you on how to do this problem). (3 pts) 3. How can one determine which...
1. How many mL of 0.100 M NaOH are required to neutralize (or titrate) 25.0 mL of 0.15 M H,Po.? Write the balanced acid-base neutralization reaction to start. (12 pts)
3 part question
Determine the theoretical yield (IN GRAMS) for 1-bromobutane if you start with 109 mmol of butanol nd excess acid and sodium bromide. (Note: the stoichiometric relationship between butanol and romobutane is 1:1) Convert the theoretical yield of 1-bromobutane to moles. Convert the moles to mmol. please clearly explain how to do this using the below information with thr correct sig figs Structure for 1-butanol Molecular weight for 1-butanol density for 1-butanol Bonpoint butanol 117.7°C 74.12 gimol 81...
please help!!
A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (II) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) – Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here
2. A 25.0 mL sample of unknown HBr is titrated with 0.100 M (NaOH). The equivalence point is reached upon the addition of 18.36 mL of the base Calculate the concentration of the unknown HBr (25 pts)
Q4 Solution Stoichiometry 10 Points A 25.0 ml of 0.527 M sodium sulfide(aq) and 55.0 ml of 0.243 Miron (III) nitrate are mixed together. What mass of solid iron (III) sulfide can be formed? What is the limiting reagent? Show your work for full credit. 3 Na2S (aq) + 2 Fe(NO3)3 (aq) ► Fe2S3 (s) + 6 NaNO3 (aq) The limiting reagent is Enter your answer here The theoretical yield of iron sulfide is Enter your answer here Please select...
3. If sodium methoxide in methanol was used in place of potassium t butanol, your GC analysis would look much more like the 2-butanol/sulfuric acid reaction products. In addition, a new, non-alkene product would be present in the GC analysis from a competing, non-elimination mechanism. Explain why the alkene distribution would change, what the new product would be, and why this new product would form. 4. If 2-bromobutane was reacted with trimethylamine to produce sec-butyl trimethyl- ammonium bromide (see below),...
E. Titration calculations 1. A 25.0-ml sample of 0.100 M HCl is titrated with 0.125 M NaOH. How many milliliters of the titrant will be need to reach the equivalence point? 2. A 25.0-ml sample of 0.100 M Ba(OH)2 is titrated with 0.125 M HCI. How many milliliters of the titrant will be need to reach the equivalence point? 3. For the following titrations, determine if the equivalence points will be acidic, basic, or neutral i. NH3 titrated with HCI...
Procedure: Measure and dispense 0.6 ml of a 4.4 M otion of sodium methoxide in methanol and me of ethanol into a 5 mL reaction vial. Add 2.5 mmol of acetaminophen (40.378. Set up for reflux in the rume hood and bring reaction to reflux for 15 minutes (solvent is boiling and vapors are condensing condenser). After 15 minutes, directly through the top of the condenser tube, carefully add 0.3 ml of iemy iodide. Continue to reflux for another 45...
0.100 molar weak acid HA vs 0.100 molar NaOH Start with 25.0 mL HA I will provide a blank graph if you want to use it to fill in the points. You can use a pencil and take a picture) or 'draw'. Or you can use a graphing program. Please answer questions, 2 points each According to this data: What is the pka of the acid? What is [H*) at the Equivalence point? What is the [OH-] at the Equivalence...
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