P(A) = 0.42
P(C) = 0.38
P(B) = 1 - 0.42 - 0.38 = 0.2
P(Time | A) = 0.47
P(Time | B) = 0.6
P(Time | C) = 0.35
P(C | Time) =
So, the probability that if a flight is on time then it is from airline C is 0.2953.
glu years old. U 10. Three airlines serve a small town in Ohio. Airline A verbeterine...