Question

the first pic is values u may need to solve 8,10 or 11

01:2.50 C, And 02-6.70 u Are Loca. Chegg.com 4. [2pt] Two charges, Q;=2.00 uC, and Q2-5.30 Care located at points (0.-2.00 cm) and (0.+2.00 cm), as shown in the figure. 22 What is the magnitude of the electric field at point P. located at (5.00 cm.0), due to Q, alone? Correct, computer gets: 6.20E+06 N/C Hint: The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remembe 5. [2pt] What is the x-component of the total electric field at P? Correct, computer gets: 2.10E+07 N/C Hint: By the principle of linear superposition, the total electric field at position Pis the vector sum of the electric field contribution from charge 1 and 6. [2pt] What is the y-component of the total electric field at P? Correct, computer gets -3.80E+06 N/C 7. [2pt] What is the magnitude of the total electric field at P? Correct, computer getsi 2.14E+07 N/C Hint: The electric field at point is a vector quantity. Review vector addition and recall that Ephrt Epx^2 +Epy 2).

Answer 1

Part 8.

From Part 5.

x-component of total electric field at point P, Epx = 2.10*10^7 N/C

From part 6.

y-component of total electric field at point P, Epy = -3.80*10^6 N/C

Now direction of net electric field will be given by:

Direction = arctan (Epy/Epx) = arctan (-3.80*10^6/(2.10*10^7))

Direction = -10.26 deg

(If you've already used above negative value, then since above is clockwise from +ve x-axis, So try 360 - 10.26 = 349.74 deg Counterclockwise from the +ve x-axis)

Part 10.

magnitude of Force on electron placed at point P will be given by:

|F| = |q|*E

|q| = charge on electron = 1.6*10^-19 C

E = 1.15*10^7 N/C

So,

|F| = 1.6*10^-19*1.15*10^7

|F| = 1.84*10^-12 = 1.84E-12 N

Part 11.

Since in case of symmetry net electric field in y-direction becomes zero, So direction of net electric field will be in positive x-axis direction, which is 0 deg.

Now we need direction of force on electron, since electron has negative charge and electric field is in positive x-axis, So on negative charge force will be in opposite direction of electric field which will be in negative x-axis

So Numerically we know that negative x-axis = 180 deg

Direction of force on electron = 180 deg

Let me know if you've any query.