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A recent national report states the marital status distribution of the male population age 18 or...

A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.8%), Married (54.6%), Widowed (3%), Divorced (10.6%). The table below shows the results of a random sample of 1932 adult men from California. Test the claim that the distribution from California is as expected at the alpha=0,10 significance level.

Complete the table by filling int he expected frequencies. Round to the nearest whole number:

Outcome Frequency Expected Frequency
Never Married 623
Married 1060
Widowed 51
Divorced 198

What is the correct statistical test to use?

What are the null and alternative hypothesis? Which is Ho and which is H1?

1. Marital status and residency are independant

2. The distribution of marital status in CA is the same as it is nationally

3. The distribution of marital status in CA is not the same as it is nationally

4. Marital status and residency are dependant

math   Statistics-And-Probability   
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Answe Date: 20/11/2018 To test the hypothesis is that the distribution of marital status in CA is not same as it is nationally at 10% level of significance. The chi-square goodness-of-fit test is used due to categorical variable The null and alternative hypothesis is, The null hypothesis is that the distribution of marital status in CA is same as it is nationally. The alternative hypothesis is that the distribution of marital status in CA is not same as it is nationally. The chi-square test statistic for goodness-of-fit test is, First, compute frequency expected then find chi-square test statistics. The expected frequency for Never Married is,

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