Please help Calculate the following for a 0.002 M aqueous solution of NH_3 (K_b = 1.75...

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Question

Please help
Calculate the following for a 0.002 M aqueous solu

Answer 1

Answer #1

3 [0H7 = 1.841x64 PH- -3277 10.2721 [HT: AnfilogE(10-24+1-1) add 4 emethere is nechangein value - Antlog(-1 ) Anti(m+n)- ト) pH : 0.2421

Answer 2

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