no. of mole = molarity volume of solution in liter
no. of mole of H2SO4 = 0.150 0.030 = 0.0045 mole
neutrilization reaction between KOH and H2SO4 is
2KOH + H2SO4 2H2O + K2SO4
According to reaction 2 mole of KOH neutilize 1 mole of H2SO4 therefore to neutrilize 0.0045 mole of H2SO4 require KOH = 0.0045 2 = 0.0090 mole of KOH
volume of solution in liter = no.of mole / molarity
volume of NaOH = 0.0090 / 0.250 = 0.036 liter = 36 ml
36 ml NaOH required
A 30.0 mL sample of 0.150 M H_2SO_4 is placed into a 125 mL Erlenmeyer flask...
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