Homework Answers
The reaction for precipitation is:
Pb(NO3)2(aq) + 2NaCl(aq) —> PbCl2 (s) + 2NaNO3 (aq)
from given reaction:
mol of NaCl required = 2*mol of Pb(NO3)2 present
so,
M(NaCl)*V(NaCl) = 2*M(Pb(NO3)2)*V(Pb(NO3)2)
0.100 M * V(NaCl) = 2*0.200 M * 75.0 mL
V(NaCl) = 300 mL
Answer: D
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