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Assume that the terminal voltage for the network shown in Figure 2 is measured to be 3.367 V, use Ohm’s law, KVL, and KCL to determine the value of each of the labeled variables.
+ V. - R; III Vout Figure 2. Schematic of network under test in Experiment 4. The parameter values are V - 6 V. R1 = 2 k2,
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Answer- The - zur tviro voo nyo zur In In / Istvo Io + 50142 Vout J I 2 22. 2K 320kn - 6v 34.7KR Applying nodal analy at nodeIz= = 3.367 - = 0.16835 mA 20 -0.4879 MA Ius 1 u R3tRu = 3.367 2.2+407 15 = B = 3-367 -0.66 MA 5-1 i Vozo volt

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