Question

In my lab we selected against sepia eye color (fruit fly) and our hypothesis was that because we selected against those with sepia eye color the "p" value was going to increase and the "q" value decrease. After the results the professor concluded that the resulted values did not supported our hypothesis, why? "q" didn't decreased?

F2 Wild Type Sepia observed expected deviation deviation squared (d2) d2/e 173 950 713 237 950 -64 64 4096 4096 5.7 17 7 Chi-square value: 22.7 F2 0.57 0.43 F3 Wild Type Sepia observed expected deviation deviation squared (d2) d2/e 455 101 556 417 139 556 -38 38 3 1444 3.5 1444 10.4 13.9 F3 0.58 0.42 Chi-square value:

Answer 1

If the population is in Hardy-Weinberg's equilbrium, the relative frequencies of alleles will not change. Here, the experimental population of fruit flies are in Hardy-Weinberg's​ equilibrium. So, p and q will not change.