Question

If 82 out of 174 customers are somewhat or very satisfied with your customer service, then what is p, the sample proportion? If you make a 95% confidence interval, what is the parameter you are estimating? Oo Op Op (Rho, the lower-case Greek r) If you want to compute a 95% confidence interval for the parameter, what are the assumptions that must be true? Othe original variable is normally distributed On2 30 On*p is large AND n*(1-p) is large (at least 5) On'p is large What is n*p?

Answer 1

Given X = 82 n = 174 p^- = x /n = 82/174 = 0.47 P^- =0.47 WE are estimating P Assumptions are The original variable is normally distributed nP is larget n(1-p) is large (at least 5) n times P^- = 0.47 times 174 = 81.78 n(1-P) = 174 times 0.53 = 92.22 Yes