Margin of error = 0.1
a) σ = 0.25
Z for 99% confidence interval = Z0.005 = 2.58
Margin of error = Z0.005 * σ / sqrt(n)
or, 0.1 = 2.58 * 0.25 / sqrt(n)
or, n = 41.6025
or, n = 42 balls
b) σ = 0.30
Z for 99% confidence interval = Z0.005 = 2.58
Margin of error = Z0.005 * σ / sqrt(n)
or, 0.1 = 2.58 * 0.30 / sqrt(n)
or, n = 59.9076
or, n = 60 balls
A population standard deviation of 0.3 in requires a large sample size. Due to increased variability in the population a larger sample size is needed to ensure desire accuracy
A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in...
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