This is Biochemistry. I need help with Q1 and Q2. Please be detailed. Thanks
Question 1
Km is the substrate concentration required to achieve half of the maximum velocity, As we see Km is less for Ac-LKKR-pNa for wild type, meaning it is a better substrate for the enzyme than aC-LKRR=pNa, whereas the opposite is true for Ns2b-N84S.
A larger Kcat means more favored product formation. For wildtype Ac-LKRR=pNa results in more product formation whereas opposite is true for Ns2b-N84S
Kcat/Km is the catalytic efficiency, meaning the ability of the enzyme to convert the bound substrate to product. For wild type Ac=LKKR-pNa has higher ratio meaning it converts a higher proportion of the substrate bound to product, i.e. it has a better enzyme for Ac=LKKR-pNa
for Ns2b-n84S as well Ac=LKKR-pNa has higher ratio meaning it converts a higher proportion of the substrate bound to product, i.e. it has a better enzyme for Ac=LKKR-pNa
This is Biochemistry. I need help with Q1 and Q2. Please be detailed. Thanks DISCUSSION HMW...