a)
t = 0.342/(0.0834/sqrt(4))
= 8.201
b)
p value = .0018
p value < 0.010
c)
yes
Consider the following summary statistics that were calculated on the difference between two dependent random samples,...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 F1 = 22.49 11 = 2.54 P1 = 15 Sample 2 F2 = 27.31 3 = 3.08 P2 = 18 Test the null hypothesis HO : H1 = 2 against the alternative hypothesis HA: MI <H2 a) To save you on calculations, I will tell you that the standard error of the difference in sample means (SE(X_1 bar - X_2 bar)) is...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 F1 = 23.65 = 2.50 p1 = 18 Sample 2 F2 = 25.62 = 3.28 p2 = 20 Test the null hypothesis Ho: P1 = r2 against the alternative hypothesis HA : H1 CH2 a) Calculate the test statistic for the Welch Approximate procedure. Round your response to at least 3 decimal places. Number b) The Welch-Satterthwaite approximation to the degrees of...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 Sample 2 x¯1=20.92 x¯2=26.80 s21=2.89 s22=3.81 n1=19 n2=15 Test the null hypothesis H0:μ1=μ2against the alternative hypothesis HA:μ1<μ2. a) Calculate the test statistic for the Welch Approximate t procedure. Round your response to at least 3 decimal places. b) The Welch-Satterthwaite approximation to the degrees of freedom is given by df = 27.983055. Using this information, determine the range in which the p-value...
Consider the following summary statistics, calculated from two independent random samples taken from normally distributed populations. Sample 1 Sample 2 x¯1=20.08 x¯2=24.51 s21=2.05 s22=3.20 n1=19 n2=16 Test the null hypothesis H0:μ1=μ2against the alternative hypothesis HA:μ1<μ2. a) Calculate the test statistic for the Welch Approximate t procedure. Round your response to at least 3 decimal places. b) The Welch-Satterthwaite approximation to the degrees of freedom is given by df = 28.610808. Using this information, determine the range in which the p-value...
1) Consider two independent random samples of sizes n1 = 14 and n2 = 14, taken from two normally distributed populations. The sample standard deviations are calculated to be s1= 1.98 and s2 = 5.71, and the sample means are x¯1=-10.2and x¯2=-2.34, respectively. Using this information, test the null hypothesis H0:μ1=μ2against the one-sided alternative HA:μ1<μ2, using Welch's 2-sample t Procedure for independent samples. a) Calculate the value for the t test statistic. Round your response to at least 2 decimal...
Summary statistics are given for independent simple random samples from two populations. Use the pooled t-tes conduct the required hypothesis test. 8) x1 = 13, 51 =5, n1 = 10, x2 = 21, 52 = 4, n2 = 14 Perform a left-tailed hypothesis test using a significance level of a = 0.05. A) Test statistic t = -1.526526 B) Test statistic t -4.355 Critical value-1.717 Critical value=-2.074 0.05 <P<0.10 P<0.005 Do not reject Ho Reject Ho C) Test statistic t...
Independent random samples, each containing 90 observations, were selected from two populations. The samples from populations 1 and 2 produced 50 and 42 successes, respectively. Test H0:(p1−p2)=0 against Ha:(p1−p2)≠0. Use α=0.04. (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that (p1−p2)=0 and accept that (p1−p2)≠0. B. There is not sufficient evidence to reject the null hypothesis that (p1−p2)=0. side note- no idea how to find a test...
(1 point) Independent random samples, each containing 90 observations, were selected from two populations. The samples from populations 1 and 2 produced 37 and 30 successes, respectively. Test H 0 :( p 1 − p 2 )=0 H0:(p1−p2)=0 against H a :( p 1 − p 2 )≠0 Ha:(p1−p2)≠0 . Use α=0.05 α=0.05 . (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that ( p 1 −...
(1 point) Independent random samples, each containing 80 observations, were selected from two populations. The samples from populations 1 and 2 produced 63 and 51 successes, respectively. Test Ho : (P-P2against Ha: (Pi -P2)>0. Use a0.01 (a) The test statistic is (b) The P-value is (c) The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that (pi - P2) - 0. B. We can reject the null hypothesis that (pi - P2) 0 and...
(1 point) Independent random samples, each containing 800 observations, were selected from two binomial populations. The samples from populations 1 and 2 produced 581 and 221 successes, respectively. (a) Test Ho : (p1 – P2) = 0 against Ha : (Pi – P2) # 0. Use a = 0.01 test statistic = rejection region |z| > The final conclusion is # 0. A. We can reject the null hypothesis that (p1 – P2) = 0 and accept that (p1 –...