Find the net torque on the wheel in the figure below about the axle through O, taking a = 5.00 cm and b = 17.0 cm. (Assume that the positive direction is counterclockwise.)
here,
a = 5 cm = 0.05 m
b = 17 cm = 0.17 m
the net torques on the wheel , T = 12 * a * cos(30) - 10 * b - 9 * b
T = 12 * 0.05 * cos(30) - 10 * 0.17 - 9 * 0.17 N.m
T = - 2.71 N.m
So the 30 degrees is irrelevant in this case. All you have to do is multiply the 12.0 N by the 0.0500 m and add this to the others.
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