Consider the electrophilic addition of one equivalent of HBr to 1-methylcyclopentadiene (1). Under the reaction conditions,...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the n electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the elect HBr by the π electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur...
(4) 6 points) Benzylic Carbocations. Reaction #1 shown below illustrates the acid catalyzed electrophilic addition of H20 to an alkene. This reaction goes through a Benzylic Carbocation Intermediate: HO. Reaction #1 H2SO4 - -- (a) Which one of the following structures is the most reasonable benzylic carbocation intermediate for Reaction #1? ANSWER: answer: он (A) (b) Based on your answer to (a), how many total resonance structures are there for this benzylic carbocation? ANSWER:
i need help with these questions 1. Under the following reaction conditions, what is the favored form of compound shown? NAOMe MeOH A. The Enol is Favored B. The Enol and Ketone are present (50:50 mixture) D. The Enolate is Favored C. The Ketone is Favored 2 What reagent best finishes the following reaction scheme. A. Br. HBR (cat) B. NaOH, Br C. HB, ROOR D. NBS, hv 3. What is the correct product for the following reaction? H2SO4 3-methyl-1-butanol...
please help me by answeing part 2. please include mechanism. Electrophilic addition of HBr to 3-methylbut-1-ene gives a mixture of two constitutional isomers. Only one of the isomers, however, is formed when the 2 methylbut 2 ene reacts with HBr in the presence of peroxides. Draw each of the isomers. Part 1: Draw the isomer that is formed in both reactions Br view structure Part 2 out of 2 Draw the isomer formed only in electrophilic addition reaction. edit structure......
Electrophilic Addition 16,44 Draw the products formed when each compound is treated with one equivalent of HBr. 10.45 Treatment of alkenes A and B with HBrave the same all halide C. Draw a mechanism for each reaction, including all reasonable resonance structures for any intermediate DOMOHON Bronson Her MCHACHA 16.46 Draw a stepwise mechanism for the following reaction.