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Problem 2 Schmidt Industries makes four different snake traps; the Harlan, the Gaylen, the Leah and the Matthew. The Harlan s
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Answer #1

1)

Load of machine A = SUMPRODUCT of Processing time and Forecast demand

= 80*10+60*10+40*5+20*5

= 1700 minutes

Load of machine B = SUMPRODUCT of Processing time and Forecast demand

= 80*15+60*10+40*10+20*5

= 2300 minutes

Load of machine C = SUMPRODUCT of Processing time and Forecast demand

= 80*15+60*10+40*15+20*5

= 2500 minutes

Load of machine D = SUMPRODUCT of Processing time and Forecast demand

= 80*5+60*10+40*10+20*10

= 1600 minutes

Load of machine C is the highest. Therefore, it is the bottleneck

1)

Work center C is the bottleneck. Hence, it is of greatest concern for the operations manager.

2)

Contribution per BN minute of Harlan model = (200-80)/15 = $ 8

Contribution per BN minute of Gaylen model = (150-60)/10 = $ 9

Contribution per BN minute of Leah model = (100-40)/15 = $ 4

Contribution per BN minute of Matthew model = (75-20)/5 = $ 11

Products are prioritized for production in order of their contribution per BN minute

Therefore, priority of products for production is: Matthew, Gaylen, Harlan and Leah

3)

BN minutes remaining on machine C after production of Matthew, Gaylen and Harlan = 2400-(20*5+60*10+80*15)

= 500 minutes

Production of Leah = 500/15 = 33 units

Optimal product mix is:

Harlan = 80

Gaylen = 60

Leah = 33

Matthew = 20

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