Question

After class last week Professor Carini and Mohammad were working on Sandy the robot. Mohammad starts to get annoying so Professor Carini throws a bowling ball at Mohammad. Mr. Carini has a height of 65.0 in and Mohammad has a height of 77.0 in. Professor Carini throws the bowling ball at Mohammad with an angle of 32.0o with respect to the horizontal. If Proessor Carini and Mohammad are 120.0 in apart, what is the initial velocity of the bowling ball, what is the time it takes the bowling ball to hit Mohammad, and what is the magnitude and direction of the bowling ball’s velocity right before it hits Mohammad in his gut!?! (HINT: 1in=0.0245m)

Answer 1

u [ 1320 Т. h = 65 in H = 77in Carini Mohammad x direction = ulos 32 direction ulos32 n Tnitial velocity along Final velocity along Displacement along direction a n = 120 inch => =) n=120x (0.0245) = 2.94m Displacement direction H-h along y =y= 77-65= 12 in = 0.294m. y = direction = usin32 initial velocity along y Let time taken the ball to hit Mohammad at by ulsoxt an => u Cos32x t = 2.99 = t = 2.94 & uCar32 = usinot let 20 = 0.294 = usin32t - 189.88 t - Igth ROUGH 2

initial Velocity = u = 6.17 mil u Casoxt= 2.94 -) 6:17x60:32 xt= 2.94 =) t= 0. 56 sec Also -> direction -) = =) Vy - My - gt Vy= Velocity (final) along y Vy = USin 32 g (t) Vy = 6.17XSin 32 - 9.8x0.56 Vy - 3.26 - 5.51 = 3 - 2.24 ms final velocity - v - Vyh + Veen = v= √ (2.24)² + (6.17XC6s 32)² 5.003+ 2737 - 5.7 ms. final velocity is 5.7 m/s Vyr =) V To Vy Tono = Vy = 2.24 0.42 = 23.18 Vr 5.23 final velocity makes an angle of 23.18 Roue with horizoktal in clockwise direction.