A water treatment plant operator treats 5 million gallons per day (MGD) of a raw surface...
A water treatment plant operator treats 5 million gallons per day (MGD) of a raw surface water with 25 mg/L of Aluminum Sulfate (Al2(SO4)3•16H2O) to remove suspended solids in the water. The untreated water contains 20mg/L total suspended solids (TSS). Assuming that the alum removes all but 2 mg/L TSS, determine the weight of sludge which must be removed each day.
Assume:
- All of the added aluminum sulfate is converted to its solid hydroxide form (Al(OH)3) and captured in the sludge solids
- The sludge removed from the process is mechanically squeezed to remove as much water as possible resulting in a sludge ‘cake’ which is 50% water by weight
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A water treatment plant operator treats 5 million gallons per
day (MGD) of a raw surface...
[3 pts] A water treatment plant consists of coagulation, flocculation, sedimentation, filtration and disinfection. The suspended...
[3 pts] A water treatment plant consists of coagulation, flocculation, sedimentation, filtration and disinfection. The suspended solids concentration in the raw water coming into the plant is 500 mg/L and the plant treats 8 MGD. Alum (Al2(S04)3 14H20) is used as a coagulant with a dose of 50 mg/L. Compute the total solid sludge produced daily if a complete reaction of alum to aluminum hydroxide (Al(OH)3] occurs and 98% total solids are removed by the sedimentation and filtration steps. The...
Example 8: A 10 MGD (million gallons per day) surface water treatment plant proposes to use...
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Environmental Engineering 3&4 So 3. An activated sludge plant treats 5 MGD and the average influent...
Environmental Engineering 3&4
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10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated...
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[3 pts] A water treatment plant consists of coagulation, flocculation, sedimentation, filtration and disinfection. The suspended solids concentration in the raw water coming into the plant is 500 mg/L and the plant treats 8 MGD. Alum (Al2(S04)3 14H20) is used as a coagulant with a dose of 50 mg/L. Compute the total solid sludge produced daily if a complete reaction of alum to aluminum hydroxide (Al(OH)3] occurs and 98% total solids are removed by the sedimentation and filtration steps. The...
Example 8: A 10 MGD (million gallons per day) surface water treatment plant proposes to use alum coagulation for turbidity reduction using 45 mg/L alum! dosage. The raw water has an alkalinity of 20 mg/L as CaCo,. Commercial alum has the formula Al(SO2)2.144,0 (MW = 594). Determine the daily alum dosage required in kg/d. Z.6 -> EW - 99
A water treatment plant with an average flow of Q-1,0 m3/s treats its water with alum at a dose of 30 mg/L. Alum coagulation is used to remove particulate matter, reduce the concentration of organic matter, and reduce the alkalinity of the water according to Equation 10-1. If the organic matter concentration is reduced from 10 mg/L to 2 mg/L. determine the total mass of Al(OH)3 removed per day O 708 kad 652 kg/d 674 O 720 kg • If...
Environmental Engineering 3&4
So 3. An activated sludge plant treats 5 MGD and the average influent BOD is 200 mg/L. The WWTP has 2 aeration basins, each 100 ft x 25 ft x 15 ft deep and 2 final clarifiers with diameters of 20 ft. About 35% of BOD is removed in primary clarifiers. Determine the BOD in the primary effluent, hydraulic retention time, F/M ratio, BOD exiting the aeration basin and mass of solids wasted (1b/d). The operation parameters...
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