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Example 8: A 10 MGD (million gallons per day) surface water treatment plant proposes to use alum coagulation for turbidity re


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1 The total amount of coater = 10 MGD = 10 X 3785411:8 L = 378 54118L (.11 MGD-378541.8 The alum close is = 45 mg/L L Means f

vo for 101MG/D = 37854118L coatens per a per day = 45X06 x 37854118 KG Alom is needed per . day = 1703435310 X10-6 kg - 1703.

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