Question

def load_locations(filename): (str) -> dict Read data from the file with the given fi lename and create and return a dictionary with location data, structured as descr ibed in the ass ignment handout, Part 1 Section I1

Python Code help needed. Based on the file (2nd picture) a dictionary like the third picture is to be made.

Answer 1

SOLUTION

f = open("file.txt", "r")
d={}
temp=0
for x in f:

    #if the line is [END DESCRIPTION] or [END ACTION] then don't store it.
    if len(x)==18 or len(x)==13:       
        temp=0
    #if the value of temp is 1 , we've encountered [END DESCRIPTION] start storing
    if temp==1:
        #store the next lines and remove the railing new lines
        d[val].append([x.strip()])        
    #if the value if temp is 2 , we've encountered [END ACTION] start storing again
    elif temp==2:
        #stripping the trailing white spaces and new line characters
        x=x.strip()
        #find the location of ' , 2.1 ' and store it in t
        t=x.find(", "+str(int(val))+".")  
        #if the dictionary has only 1 list by the key add one more for [START ACTION] lines
        if len(d[val])==1:
            #Adding another list
            d[val].append([])              

        #Adding lines after [START ACTION] in a tuple and using the position of ' , 2.1' in t
        d[val][1].append((x[:t],float(x[t+2:])))
    try:
        #Check if the line have number then convert it to float
        val=float(x)
        #Form the number as a key to an empty list
        d[val]=[]
    except ValueError:
    #if the line above doesn't have a number it'll encounter this part
    
        #assign 1 if line is [START DESCRIPTION] whose length is 20, 2 if line is [START ACTION] whose length is 15and 0 otherwise
        if len(x)==20:
            temp=1
        elif len(x)==15:
            temp=2
print(d)

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THANKS!