Question

CRA CDs Inc. wants the mean lengths of the “cuts” on a CD to be 170 seconds (2 minutes and 50 seconds). This will allow the disk jockeys to have plenty of time for commercials within each 10-minute segment. Assume the distribution of the length of the cuts follows a normal distribution with a standard deviation of nine seconds. Suppose that we select a sample of 16 cuts from various CDs sold by CRA CDs Inc. Use Appendix B.1 for the z-values.

a. What can we say about the shape of the distribution of the sample mean?

Sample mean is normal

b. What is the standard error of the mean? (Round the final answer to 2 decimal places.)

Standard error of the mean 2.25 seconds.

c. What percentage of the sample means will be greater than 174 seconds? (Round the final answer to 2 decimal places.)

Sample means             %

d. What percentage of the sample means will be greater than 166 seconds? (Round the final answer to 2 decimal places.)

Sample means             %

e. What percentage of the sample means will be greater than 166 but less than 174 seconds? (Round the final answer to 2 decimal places.)

Appendix B.1 Areas under the Normal Curve Examale Iz196. then P0 to z)0.4750 04750 96 0.00 0.09 0.01 0.08 0.02 0,07 0.03 0.06

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Answer #1

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