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3. As we will soon lean, under certain reaction conditions it is possible to react hydrocarbons to give all possible monochloro derivatives as products, i.e. where one C-H bond is replaced by a C-Cl bond. The following isomers with the formula CsH12 were reacted under these conditions to produce products with the formula CsH11C CsH1Cl. Using various physical experimental methods it is possible to separate all of the possible CsH11CI isomers derived from each CSH12 isomer. Draw Kekulé or bond- line structures for each CsH12 isomer with the following properties. a. A CsH12 isomer that gives three CsH1CI derivatives b. A CsH12 isomer that gives four CsH1Cl derivatives. c. A CsH12 isomer that gives only one CsH11Cl derivative. d. Do any other CsH12 isomers exist and, if so, how many CsH1CI derivatives can be formed from each of them? WO e. Based on your answer to (c), can you think of a Csthe hydrocarbon that can give only one possible CeH1/CI derivative? Draw the structure of this hydrocarbon and its monochloro derivative.
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Sec- pentane hovw, -to fo Orm Chloride derivahve of e above pentaw. Replace A.) Tabin Co 2 sec. pentan → 2- LI

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