Question

A particle is released as part of an experiment. Its speed t seconds after release is given by v(t) = -0.56 +12, where vt) is in motors per second. a) How far does the particle travel during the first 6 sec? b) How far does it travel during the second 6 sec? a) The particle travels meters in the first 6 sec. (Round to two decimal places as needed.) b) The particle travels meters in the second 6 sec. (Round to two decimal places as needed.)

Answer 1

hope this will help you

ult) = -0.5t² + 12t (a) -0. 5t * 662 Distance travelled in first 6 seconds - - 0.5t + 12+) it = -0.5t + 6+2 I = -0.5163361632 = -36 +216 = (180) meters 0.5t² + 12+) dt 3 (6) In next 6 seconds 12 6+2 + ost² +12t) dt = -0.5t 3 = -0.5 (12) 3 6(12) ² - / -36 +216) = 1396 meters