The execution of the above Turing machine can be simulated using this table-
Here Bold character indicated the position of machine on string.
1##1 -
Curr. State | Curr. string | Curr. Character | Move(L/R) | New character | New state | Changed string |
---|---|---|---|---|---|---|
q1 | 1##1 | 1 | R | x | q3 | x##1 |
q3 | x##1 | # | R | - | q5 |
x##1 |
q5 | x##1 | # | R | - | REJECTED |
Now the transition is not defined for symbol # in state q5. So it rejects the string 1##1.
It can be written as-
[q1]1##1 -> x[q3]##1 -> x#[q5]#1 -> REJECT
------------------------------------------------------------------------------------------------------------
0#0-
So the string is accepted.
It can be written as-
[q1]0#0 -> x[q2]#0 -> x#[q4]0 -> x[q6]#x -> [q7]x#x -> x[q1]#x -> x#[q8]x -> x#x[q8] -> ACCEPT
Please note that that the table was there just for explanation, the lines in bold were the actual notation used for turing machines.
I hope it helps. For any doubt, feel free to ask in comments, and
give upvote if u get the answer.
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