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Problem 24.06 phencal mimor Part D curvanure of 100 Calculabe the size of the image Correct...
PART A= -3.61 CM PART C= -3.20 CM PART E= -1.73 CM PLEASE ANSWER ALL PARTS....
PART A= -3.61 CM
PART C= -3.20 CM
PART E= -1.73 CM
PLEASE ANSWER ALL PARTS. I WILL GIVE GOOD
RATING!
Problem 24.06 Problem 24.06 Part B A convex spherical mirror has a radius of curvature of 9.40 cm A convex spherical mirror has a radius of curvature of 9.40 cm Calculate the size of the image. Correct VIII AΣ ? Part F y' - mm Calculate the size of the image. Submit Request Answer ΤΟΙ ΑΣφ ? Part C...
Need help with part f only (23 %) Problem 10: Kiki places her kitty cat Jiji...
Need help with part f only
(23 %) Problem 10: Kiki places her kitty cat Jiji 25 cm in front of a plane mirror and then Kiki stands 65 cm away from the mirror 17% Part (a) How far behind the mirror, in cm, does Jiji see himself? 25 Correct! 17% Part (b) How far behind the mirror, in cm, does Kiki see Jiji? -25 Correct! 17% Part (c) How far behind the mirror, in cm, does Kiki see herself?...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
Part A and B (14%) Problem 3: An object is located a distance d .-5.1 cm...
Part A and B
(14%) Problem 3: An object is located a distance d .-5.1 cm in front of a concave mirror with a radius of curvature r: 20.9 cm 33% Part (a) Write an expression for the image distance, di Potential 100% (DI 7 | 8 | 9 % per attempt) 0 Hint 2 d, in 33% Part (c) Is this a real or virtual image? Virtual Correct
Part C, D and E please (6%) Problem 11: A capacitor of capacitance -8.5 F is...
Part C, D and E please
(6%) Problem 11: A capacitor of capacitance -8.5 F is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor of resistance R-15 k2, and a battery which provides a potential difference of VB 135 V 20% Part (a) Immediately after the switch is closed, what is the voltage drop VC, in volts, across the capacitor? VC-0 Correct! 20% Part (b) Immediately after the switch is closed, what is...
For part (b), An algorithm takes 0.5 ms for input size 100. How large a problem...
For part (b), An algorithm takes 0.5 ms for input size 100. How large a problem can be solved in 1 min if the running time is the following (assume low-order terms are negligible): a. linear b. O(NlogN) c. quadratic d. cubic
The type of lens is not given. (10%) Problem 6: Two lenses are mounted d= 29 cm apart on an optical bench. The focal len...
The type of lens is not
given.
(10%) Problem 6: Two lenses are mounted d= 29 cm apart on an optical bench. The focal length of the first lens is fı = 7.9 cm and that of the second lens is f2 = 5.6 cm. An object of height ho = 3.4 cm is placed at a distance of do = 29 cm in front of the first lens. 25% Part (a) Ignoring the second lens for now, at what...
9:53イ Correct Problem 21.50 Tap image to z0om Part A Find the electic ele E imagnitude...
9:53イ Correct Problem 21.50 Tap image to z0om Part A Find the electic ele E imagnitude and dnection) at poire P Hint Remember sinl-6)so the two halves of the rod ane opposinely charged Correct the acceleration (magnitude and lection placed at point P assuming R-1.3 cm and A 20 pC/m Express your anewer using twp significant figures 335-10 Incorrect, Try Again; 4 attempts remaining
A) where is the image located ?? C) What is its magnification?? (3396) Problem 1: An...
A) where is the image located ??
C) What is its magnification??
(3396) Problem 1: An object is located 2 cm away from a converging lens with a focal length of 5 cm. 25% Part (a) where is the image located (in cm)? Grade Summary Deductions Potential 0% 100% sin( tan)T acos cosO Submissions Attempts remaining: 20 (000 per attempt) detailed view cotanasin0 atanacota sinh cosh tah cotanh) Degrees Radians DEL CLEAR Submit I give up! Hints: 0 for a...
(10%) Problem 7: An object of height h, is placed a distance do in front of...
(10%) Problem 7: An object of height h, is placed a distance do in front of a converging lens of focal length f. 50% Part (a) Write an equation for the image distance using variables from the problem statement. d; =(-d. f)(f-do) Correct! > * 50% Part (b) Write an equation for the height of the image using variables from the problem statement. h;= (- do fh, d. (f-do) Grade Summary Deductions 3% Potential 97% B y d. h. f...
PART A= -3.61 CM
PART C= -3.20 CM
PART E= -1.73 CM
PLEASE ANSWER ALL PARTS. I WILL GIVE GOOD
RATING!
Problem 24.06 Problem 24.06 Part B A convex spherical mirror has a radius of curvature of 9.40 cm A convex spherical mirror has a radius of curvature of 9.40 cm Calculate the size of the image. Correct VIII AΣ ? Part F y' - mm Calculate the size of the image. Submit Request Answer ΤΟΙ ΑΣφ ? Part C...
Need help with part f only
(23 %) Problem 10: Kiki places her kitty cat Jiji 25 cm in front of a plane mirror and then Kiki stands 65 cm away from the mirror 17% Part (a) How far behind the mirror, in cm, does Jiji see himself? 25 Correct! 17% Part (b) How far behind the mirror, in cm, does Kiki see Jiji? -25 Correct! 17% Part (c) How far behind the mirror, in cm, does Kiki see herself?...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
Part A and B
(14%) Problem 3: An object is located a distance d .-5.1 cm in front of a concave mirror with a radius of curvature r: 20.9 cm 33% Part (a) Write an expression for the image distance, di Potential 100% (DI 7 | 8 | 9 % per attempt) 0 Hint 2 d, in 33% Part (c) Is this a real or virtual image? Virtual Correct
Part C, D and E please
(6%) Problem 11: A capacitor of capacitance -8.5 F is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor of resistance R-15 k2, and a battery which provides a potential difference of VB 135 V 20% Part (a) Immediately after the switch is closed, what is the voltage drop VC, in volts, across the capacitor? VC-0 Correct! 20% Part (b) Immediately after the switch is closed, what is...
The type of lens is not
given.
(10%) Problem 6: Two lenses are mounted d= 29 cm apart on an optical bench. The focal length of the first lens is fı = 7.9 cm and that of the second lens is f2 = 5.6 cm. An object of height ho = 3.4 cm is placed at a distance of do = 29 cm in front of the first lens. 25% Part (a) Ignoring the second lens for now, at what...
9:53イ Correct Problem 21.50 Tap image to z0om Part A Find the electic ele E imagnitude and dnection) at poire P Hint Remember sinl-6)so the two halves of the rod ane opposinely charged Correct the acceleration (magnitude and lection placed at point P assuming R-1.3 cm and A 20 pC/m Express your anewer using twp significant figures 335-10 Incorrect, Try Again; 4 attempts remaining
A) where is the image located ??
C) What is its magnification??
(3396) Problem 1: An object is located 2 cm away from a converging lens with a focal length of 5 cm. 25% Part (a) where is the image located (in cm)? Grade Summary Deductions Potential 0% 100% sin( tan)T acos cosO Submissions Attempts remaining: 20 (000 per attempt) detailed view cotanasin0 atanacota sinh cosh tah cotanh) Degrees Radians DEL CLEAR Submit I give up! Hints: 0 for a...
(10%) Problem 7: An object of height h, is placed a distance do in front of a converging lens of focal length f. 50% Part (a) Write an equation for the image distance using variables from the problem statement. d; =(-d. f)(f-do) Correct! > * 50% Part (b) Write an equation for the height of the image using variables from the problem statement. h;= (- do fh, d. (f-do) Grade Summary Deductions 3% Potential 97% B y d. h. f...
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