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A penny is placed at the outer edge of a disk (radius = 0.122 m) that...

A penny is placed at the outer edge of a disk (radius = 0.122 m) that rotates about an axis perpendicular to the plane of the disk at its center. The period of the rotation is 1.54 s. Find the minimum coefficient of friction necessary to allow the penny to rotate along the disk. (Answer in units)

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Given, Time period of disk-T 1.54 sec. Radius of disk R-0.122 m Lets find the angular speed of disk, 2 2X3.14 T1.54 angular speed is defined as rad l s= 4.08 rad / s ω Since, mass of disk is very very greater than the penny. So, when penny is placed on the outer edge of the disk, then, angular speed of penny with disk does not change appreciable. Then, we take angular speed of the disk+ penny same So, when penny revolves around the axis of disk, then, it experience the centripetal force that would be equal to the static friction Cetripetal force friction force Disk lusCoefficient of friction is unitless quantity.

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