What is So for
the reaction 2CH3OH(g) + 3O2(g)
------> 2CO2(g) +
4H2O(g)
ans) 88.0 J/K
Explanation
What is entropy?
The randomness and the molecule disorder rely on the available different arrangements in a given reaction or a system is characterised by a thermodynamic quantity called entropy, Which is denoted by the letter S.
Here the question is about So
which is called Standard Entropy Change
Standard Entropy Change
The difference between the total no.of standard product entropies and the total no.of standard reactant entropies will give the value for Standard Entropy Change.
Sorxn
is the symbol for Standard Entropy Change. The SI unit will be
J/mol.K.
Formula for the calculating the Standard Entropy Change
Sorxn
=
n.So
(products) -
n.So
(reactants)
So (reactants) = Standard entropy value for the reactants
So (products) = Standard entropy value for the products
n = significant for the entropy of each compound should be multiplied by its coefficients in the balanced equation.
According to the equation 2CH3OH(g) + 3O2(g) ------> 2CO2(g) + 4H2O(g)
Standard entropy value for CH3OH(g) = 239.7 J/mol.K
Standard entropy value for O2(g) = 205 J/mol.K
Standard entropy value for CO2(g) = 213.67 J/mol.K
Standard entropy value for H2O(g) = 188.7 J/mol.K
The formula for calculating the Standard Change in entropy for this specific reaction is
Sorxn
= [2.So(CO2 (g)) + 4.So
(H2O) (g))] - 2.So(CH3OH (g)) +
3.So (O2) (g))]
Applying these values in the formula
Sorxn
= [ 2(213.67 J / mol.K) + 4(188.7 J/mol.K)] - [ 2 (239.7 J / mol.K)
+ 3(205 J / mol.K)]
= [427.34 J /mol.K + 754.8 J / mol.K] - [479.4 J / mol.K + 615 J / mol.K]
= 1182.14 J /mol.K - 1094.4 J / mol.K
= 87.74 J / mol.K
By taking as the whole number for the answer will be
So for
the reaction 2CH3OH(g) + 3O2(g)
------> 2CO2(g) + 4H2O(g) =
88.0 J
/mol.K
Question 21 (1 point) What is As for the reaction 2CH2OH(g) + 302(g) →2C02(g) + 4H20(8):...
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(3) 4H1\g) +U, g) — 21,(s) + 2H,Ulg) E2C.6(a) For the reaction C,H,OH(1) + 302(g) → 2C02(g) + 3 H2O(g), 4,UⓇ = -1373 kJ mol" at 298 K. Calculate A.HⓇ
Consider a fuel cell that uses the reaction C2H4(g) + 302(g) + 2C02(g) + 2H2O(1) Using the standard free energies of formation, what is the value of Eº for the cell reaction? Substance and State AG (kJ/mol) C2H4 (8) 68.1 CO2(g) -394.4 H2O(1) -237.2 O2(g) 0 Express your answer with the appropriate units. C: HÅR O a ? Eº = 0.0138 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
For the following reaction: C2H4(9) +302(g) + 2C02(g) + 2H2O(1) What is the change in free energy in kJ ? The relevant standard free energies of formation are: kJ AG . C.H. = 68.4- mol mol AG, 0, = 0 AGC, CO, = -393.3 kJ AGF, 4,0 = -285.8 kJ mol mol • Your answer should include three significant figures.
2. Given the following reaction: 2CH2OH(g) + 302(g) → 2CO2(g) + 4H2O(g) Delta Gº Kj/mol -163 CH2OH O, CO2 H20 -394 -229 What is Delta G for the reaction
Consider a fuel cell that uses the reaction C2H4(g) + 302(g) → 2C02(g) + 2H2O(1) Using the standard free energies of formation, what is the value of Eº for the cell reaction? Substance and State AG(kJ/mol) C2H4(g) 68.1 CO2(g) -394.4 H2O(1) -237.2 02(g) 0 Express your answer with the appropriate units. I HÅR O 2 ? E° = 3.45 V Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining
eLearning Taking Pool 6 1. Consider the balanced equation for the following reaction: 302(g) + 2CH2OH() → 2C020) + 4H2011) Determine how much excess reactant remains in this reaction if 5.84 moles of Oz reacts with 1.23 moles of CH3OH. O 4.00 moles 0.62 moles 3.89 moles 0.92 moles O 1.95 moles Use the slider to rate your confidence on this question. 100 Not at all confident Very confident save submit
29.0 g
Part E Determine the limiting reactant. CH, OH(1) + 302(g) +2C02(g) + 3H2O(g) Express your answer as a chemical formula. 02 Submit Previous Answers ✓ Correct Part F Calculate the grams of product in parentheses that would be produced. (H2O) Express your answer with the appropriate units. ? THE Å Value 0 a Units m(H,0) = Type here to search O E A
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