How many grams of sodium phosphate, Na3PO4, must be dissolved to prepare 400. mL of a 0.182 M aqueous solution of the salt?
Form the general equation of Molarity, we solve for moles and then, the mass:
M = moles / V
moles = m/MM
Replacing this, in the expression of molarity:
M = m / MM * V solving for mass:
m = MM * V * M
The MM is: (3*23) + 31 + 16*4 = 164 g/mol
m = 164 g/mol * 0.400 L * 0.182 mol/L
m = 11.9392 g
Hope this helps
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