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and Vpp = 18 V - Cc2 w S R = 500 k2 SRL W Žr {Rs -ov Figure P4.27 Figure P4.26 For the common-source amplifier shown in Figur
iconductor Devices and Basic Applications drain resistor is Rp = 4k92. (a) Determine lo such that VSDQ = 5 V. (b) Find the sm
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Sol a) Here Voso = su SR-500 Now by writing KvL in Orain - Source g - Vsno - IoRo = -9 Io = 13 13 13 = Toro = - Iq = 3.25 MAVo = + Iokollro) Vo = + 9m Vsg x[Roll ro) Vo = go (vi) (Rouro) Won -gmRo = - 8.33 mm * (4x(0.21) ma 14.25 vi 2-24 (voldage gaplease provide rating for this answer

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