Homework Answers
Since there is no friction, only two forces are acting along incline, one is tension which is pulling up the plane and component of gravitational force, pulling down the plane.
The component of gravitational force along incline is mg*sin(15)
Net force = T- mg*sin15o
Net force = 25 - 5*9.81*sin(15o)
Net force = 12.305 N up the plane
1) Acceleration = force/mass = 12.305/5
a = 2.46 m/s
2) Normal force is component of weight
N = mg*cos(15)
N = 47.38 Newtons
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Newton's Laws of Motion
Consider an inclined plane with inclination angle theta. The magnitude of the friction force is mu times the magnitude of the normal force. F_f = mu F_N. Find the component of the total force along the plane on a block of mass M sliding down the inclined plane, and the acceleration down the plane. Note that the acceleration is the same for all bodies: it Is independent of the mass M of the body.
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1. The figure shows a box with mass m1 on a
frictionless plane inclined at angle ?1. The
box is
connected via a cord of negligible mass to another
box with mass m2 on a frictionless plane
inclined at
angle ?2 (> ?1). The pulley
is frictionless and has
negligible mass and assumes that the setup is on the
surface of the earth.
a) Provide free-body force diagram for both boxes.
b) What is the acceleration in terms of m1,...
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