Question

Please Complete all parts of 1-5

Toss Number of Candies Number Landing Completely on Base 6 6 5 Total

Answer 1

Here P = x bar/5: where x bar = sigma^n_i = 1 f_ix_i/N x bar = (1) (5) + (2) (6) + (3) (6) + (4) (5) + (5) (4) /5 + 6 + 6 + 5 + 4 = 5 + 12 + 18 + 20 + 20/26 = 2. 8846 p = 2. 8846/5 = 0. 5769 a) Hypothesis: (claim): population proportion of kisses chocolates that land completely on the base is 50% (i. e) p = 0. 5 NULL Hypothesis: p = 0. 5 alternative hypothesis: p notequalto 0. 5 \r\n b) d = 10% = level of significance = 0. 1 c) Test statistic z = p - p/squareroot p(1 - p) /n = 0. 5769 - 0. 5/squareroot (0. 5) (1 - 0. 5) /50 = 1. 0876 = 1. 08 d) p - value = p(z > 1. 08 (or) z < -1. 08) = 0. 2767 e) 0. 2767 > 0. 1 We accept H_0 (i. e) fail to reject H_0 f) the equation proportion of kisses chocolates that land completely on the base is 50% \r\n a) claim: population proportion of kisses chocolates that cancel completely on the base is 40%