A 9 kg sled is initially at rest on a horizontal frictionless road. The sled is pulled a distance of 3.1m by a force of 45N applied to the sled at an angled of 30 degrees to the horizontal. Find the change in the kinetic energy of the sled
chenge in kinetic energy = work done by net force = F*S*cos(30) = 45*3.1*cos(30) = 120.81 J
change in K.E K2-K1=F.s
K2-K1=Fcos(theta)*s
=45*cos(30)*3.1
=120.81 J....is answer
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